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A rock is thrown from the top of a ladder. The function

h(t) = –16t2 + 120t + 10 gives the height of the rock t seconds after it is
thrown a certain number of feet.
What is the height of the rock at 5 seconds?

1 Answer

5 votes

Answer:

h'(t)=88

Explanation:

h'(t)=d/dt (-16t x 2 + 120t + 10

h'(t)=d/dt (-32t + 120t + 10)

h'(t)=d/dt (88t + 10)

h'(t)=d/dt (88t) + d/dt (10)

h'(t)=88 + 0

User Pratik Tiwari
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