Question

In a vacancy for a position of animal breeder in an organization, then criteria of selection were work experience, entrance exam, and interview results. The relative importance of these criteria was regarded to be different. The weights of these criteria and scores obtained by 3 candidates (out of 100 in each criterion) are given in the following table. In addition, the selection of a candidate is based on the average result on these criteria, (full question attached)​

Answer 1

To determine the most suitable candidate we will calculate their total scores and see who's the best.

first for mr X

work experience = 70

score = work experience x wieght = 70 x 4 = 280

Entrance = 78

score = 78 x 3 = 234

Interview = 70

score = 70 x 4 = 210

total score = 280 + 234 + 280 = 794

for mr Y

Work experience = 89

score = 89 x 4 = 356

Entrance = 83

score = 83 x 3 = 249

Interview = 89

Score = 89 x 4 = 356

Total score = 356 + 249 + 356 = 961

for mr Z

work experience = 85

score = 85 x 4 = 340

Entrance = 89

Score = 89 x 3 = 267

Interview = 85

Score = 85 x 4 = 340

Total score = 340 + 267 + 340 = 947

So as we can see Mr Y has best score therefore I think he's the best for the job.

Answer 2

Step-by-step explanation:

`\sf Average \ Result : (sum \ of \ value \ of \ scores)/(sum \ of \ weight)`

Workout:

`\sf For \ candidate \ X = (70 \ \cdot \ 4 \ + 78 \ \cdot \ 3 \ + 70 \ \cdot \ 4 )/(4 + 3 + 4) = 72.18 \ \ average \ score`

`\sf For \ candidate \ Y = (89 \ \cdot \ 4 \ + 83 \ \cdot \ 3 \ + 89 \ \cdot \ 4 )/(4 + 3 + 4) = 87.36 \ \ average \ score`

`\sf For \ candidate \ Z = (85 \ \cdot \ 4 \ + 89 \ \cdot \ 3 \ + 85 \ \cdot \ 4 )/(4 + 3 + 4) = 86.09 \ \ average \ score`

Conclusion:

Among all of them, candidate Y has the best average score of about 87.36 whereas candidate Z has second best score of 86.09 average score and candidate X has the least average score of 72.18.

Candidate Y is the appropriate candidate for this position on the criteria.