Answer:
ΔT = 66.06°C
Step-by-step explanation:
Given data:
Mass of iron = 750 g
Heat absorbed = 22000 j
Change in temperature = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
specific heat capacity of iron is 0.444 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
By putting values,
22000 j = 750 g × 0.444 J/g.°C × ΔT
22000 j = 333 J/°C × ΔT
ΔT = 22000 j /333 J/°C
ΔT = 66.06°C