Question

If a rectangle has the sides 5x-3 and 6x-4 what is the area and perimeter

Answer 1

Explanation:

`A = lw`

`A=(5x-3)(6x-4)`

`A=30x^2-20x-18x+12`

`A=30^2-28x+12`

`P=2(l + w)`

`P = 2(5x - 3 + 6x - 4)\\P=2(x-7)\\P=2x-14`

Answer 2

`Perimeter = 22x - 14`

`Area = 30 {x}^(2) - 38x + 12`

Explanation:

Length of rectangle (l) = 5x - 3

Weidth of rectangle (w) = 6x - 4

Perimeter of the rectangle =
`2(l + w)`

`= > 2(5x - 3 + 6x - 4)`

`= > 2(11x - 7)`

`= > 22x - 14`

Area of the rectangle =
`l * w`

`= > (5x - 3)(6x - 4)`

`= > 5x(6x - 4) - 3(6x -4)`

`= > 30 {x}^(2) - 20x - 18x + 12`

`= > 30 {x}^(2) - 38x + 12`