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Need helpppp i have no idea what to do

Need helpppp i have no idea what to do-example-1

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Answer:

Line 1 and Line 2: Perpendicular

Line 1 and Line 3: Neither

Line 2 and Line 3: Neither

Explanation:

We will write all lines in slope intercept form i.e
y=mx+b

where m is slope.

And check

a) If two lines are parallel they have same slope
m_1=m_2

b) If two lines are perpendicular they have opposite reciprocal slopes i.e
m_1=-(1)/(m_2)

Equation for Line 1:
y=-(4)/(3)x-4

Already in slope-intercept form

Slope for Line 1 m is:
\mathbf{m_1=-(4)/(3)}

Equation for Line 2:
6x-8y=-6

Converting into slope-intercept form:


6x-8y=-6\\-8y=-6x-6\\y=(-6x-6)/(-8)\\y=(-6x)/(-8)+(-6)/(-8) \\y=(3x)/(4)+(3)/(4)

Slope for Line 2 m is:
\mathbf{m_2=(3)/(4)}

Equation for Line 3:
-4y=3x+7

Converting into slope-intercept form:


-4y=3x+7\\y=-(3)/(4) -(7)/(4)

Slope for Line 3 m is:
\mathbf{m_3=-(3)/(4)}

Now, finding answers

Line 1 and Line 2

Checking their slopes:
\mathbf{m_1=-(4)/(3)},
\mathbf{m_2=(3)/(4)}

Both lines are perpendicular because they have opposite reciprocal slopes

Line 1 and Line 3

Checking their slopes:
\mathbf{m_1=-(4)/(3)},
\mathbf{m_3=-(3)/(4)}

Slopes are neither same, nor opposite reciprocal, so they are neither

Line 2 and Line 3

Checking their slopes:
\mathbf{m_2=(3)/(4)},
\mathbf{m_3=-(3)/(4)}

Slopes are neither same, nor opposite reciprocal, so they are neither

The answers are:

Line 1 and Line 2: Perpendicular

Line 1 and Line 3: Neither

Line 2 and Line 3: Neither

User Jack Chu
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