Question

What is the period of an object that makes 6 revolutions a minute?

Answer 1

T = 10 s

Step-by-step explanation:

First, we need to find the frequency of the object as follows:

`Frequency = f = (Speed\ in\ rpm)/(60)`

where,

Speed = Angular Speed = 6 rpm

Therefore,

`f = (6\ rpm)/(60)\\\\f = 0.1\ Hz`

Now, for time period (T):

`Time\ Period = T = (1)/(f)\\\\T = (1)/(0.1\ Hz)\\\\`

T = 10 s