Question

A 0.5 kg ball was kicked and was going 15 m/s.What is the kinetic energy of the ball?

Answer 1

`\boxed {\boxed {\sf 56.25 \ Joules}}`

Step-by-step explanation:

Kinetic energy can be found using the following formula:

`E_k=(1)/(2)mv^2`

where m is the mass and v is the velocity.

The mass of the ball is 0.5 kilograms and the velocity is 15 meters per second

`m= 0.5 \ kg \\v= 15 \ m/s \\`

Substitute the values into the formula.

`E_k=(1)/(2) (0.5 \ kg ) * (15 \ m/s)^2`

First, evaluate the exponent.

• (15 m/s)²= (15 m/s) * (15 m/s) = 225 m²/s²

`E_k=(1)/(2) (0.5 \ kg ) *(225 \ m^2/s^2)`

Multiply 0.5 kg by 225 m²/s²

`E_k=(1)/(2)(112.5 \ kg* m^2/s^2)`

Multiply 112 kg*m²/s² by 1/2, or divide by 2.

`E_k=56.25 \ kg*m^2/s^2`

• 1 kg*m²/s² is equal to 1 Joule
• Therefore, our answer of 56.25 kg*m²/s² is equal to 56.25 Joules.

`E_k= 56.25 \ J`

The kinetic energy of the ball is 56.25 Joules