Answer:
The distance between w=1+2i and z=3-i is 3.61
Explanation:
We need to find the distance between w=1+2i and z=3-i
The formula used is:
![Distance=√((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y4m7yqgt8t3avbuucywckv67ewv4swgsq7.png)
We have
![x_1=1, y_1=2, x_2=3, y_2=1](https://img.qammunity.org/2021/formulas/mathematics/college/bp459fwq6a8jqjufa6m4vj4782rbxc6mr9.png)
We will use only real numbers and not i for calculating distance.
Putting values and finding distance
![Distance=√((x_1-x_2)^2+(y_1-y_2)^2)\\Distance=√((1-3)^2+(-1-2)^2) \\Distance=√((-2)^2+(-3)^2) \\Distance=√(4+9) \\Distance=√(13)\\Distance=3.61](https://img.qammunity.org/2021/formulas/mathematics/college/szrpbm121baem5987wk4zx9mm43mvp5vbv.png)
So, The distance between w=1+2i and z=3-i is 3.61