Question

How many grams of nitrogen,
N2, would be required to create 9.3
moles ammonia, NH3?

Answer 1

N₂+3H₂⇔2NH₃

moles N₂ = 1/2 x 9.3 = 4.65

mass N₂ = 4.65 x 28 g/mol = 130.2 g

Answer 2

Step-by-step explanation:

Hi there!

N₂+3H₂⇋2NH₃

The molecular mass of NH₃ is 34

The mass of N₂ is 28 and mass of H₂ is 2.

Then,

2 moles of NH₃ is created by 28 g of N₂

1 moles of NH₃ is created by 28/2 g of N₂

9.3g of NH₃ is created by (28/2)*9.3 moles of N₂

Therefore, 130.2 g of N₂ is required to create 9.3 moles of NH₃.

Hope it helps!