(a+b)^2=10 and ab=1 then find a^2+b^2

$\underline{\large \bf{Required \: Answer}} : -$

$\dashrightarrow \: \red{\large8}$

$\sf$

$\underline{ \large{ \rm \pink{SolutioN}}} \: -$

$\quad \qquad\sf \: {(a + b)}^(2) = 10$

$\qquad \: \: \to\: \: \sf{a}^(2) + {b}^(2) + 2ab = 10$

$\qquad\: \: \to\: \: \sf{a}^(2) + {b}^(2) + 2(1) = 10$

$\qquad\: \: \to\: \: \sf \: {a}^(2) + {b}^(2) = 10 - 2$

$\qquad\: \:\bf \to\: \: \: {a}^(2) + {b}^(2) = 8$

$\sf$

$\sf \therefore \: 8 \: \: is \: \: the \: \: required \: \: answer$

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