Answer:
x = -1, and y = -9
Explanation:
This is done by solving one of the two equations for x or y, then substituting it in place of that variable in the other equation.
Since y is already clearly defined in the second equation let's go with that:






Now we can replace x in the equation for y with -1:



To make sure our answers are correct, let's substitute them into the original equations:

Good, let's test the other equation

So we know that our answer is correct.