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Find angle 1

(5x+6)° and (7x-18)°

Find angle 1 (5x+6)° and (7x-18)°-example-1
User Alex Getty
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1 Answer

6 votes

Answer:

Explanation:

<1 is the supplement of 5x + 5. You have to assume that the almost horizontal lines are parallel. In addition, two angles on the same side of a transversal across two parallel lines and are interior angles are supplementary.

5x + 6 + 7x - 18 = 180 Add like terms

12x - 12 = 180 Add 12 to both sides

12x = 180 + 12

12x = 192 Divide by 12

x = 192 /12

x = 6

====================

5x + 6 = 5*12 + 6

5x + 6 = 60 + 6

5x + 6 = 66

<1 + 66 = 180

<1 = 180 - 66

<1 = 114

User Quin
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