83.8k views
3 votes
Find angle 1

(5x+6)° and (7x-18)°

Find angle 1 (5x+6)° and (7x-18)°-example-1
User Alex Getty
by
8.6k points

1 Answer

6 votes

Answer:

Explanation:

<1 is the supplement of 5x + 5. You have to assume that the almost horizontal lines are parallel. In addition, two angles on the same side of a transversal across two parallel lines and are interior angles are supplementary.

5x + 6 + 7x - 18 = 180 Add like terms

12x - 12 = 180 Add 12 to both sides

12x = 180 + 12

12x = 192 Divide by 12

x = 192 /12

x = 6

====================

5x + 6 = 5*12 + 6

5x + 6 = 60 + 6

5x + 6 = 66

<1 + 66 = 180

<1 = 180 - 66

<1 = 114

User Quin
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories