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Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be simple, I need these done asap, I’d appreciate work shown C:

1) - 4 + 3x = 4 x - 8
2) -5x - 8 = 2
3) 12 r - 14 = 5 ( 2 - r )
4) 3 x - 8 = - ( 17 + 2x)
Ty!

Yo! Solving linear equations with integers! These are just some practice exercises-example-1
User Markratledge
by
3.0k points

2 Answers

23 votes
23 votes

Answer:

1) x = 4

2) x = -2

3)
r= (24)/(7)
(1(7)/(17))

4)
x=-(9)/(5)
(-1(4)/(5))

Explanation:

hope this helps!!

(work shown in photo :) )

Yo! Solving linear equations with integers! These are just some practice exercises-example-1
User Earl
by
2.7k points
22 votes
22 votes

Answer:

Explanation:

Solving linear equation with one variable:

1) -4 + 3x = 4x - 8

Add 4 to both sides

-4 + 3x + 4 = 4x - 8 + 4

3x = 4x - 4

Subtract 4x from both sides,

3x - 4x = -4x + 4x - 4

-x = -4


\sf \boxed{\bf x = 4}

2) -5x - 8 = 2

Add 8 to both sides

-5x - 8 + 8 = 2 + 8

-5x = 10

Divide both sides by (-5)


\sf (-5)/(-5)x =(10)/(-5)


\sf \boxed{\bf x = -2}

3) 12r - 14 = 5(2-r)

12r - 14 = 5*2 - 5*r

12r - 14 = 10 - 5r

Add 14 to both sides

12r - 14 + 14 = 10 - 5r + 14

12r = 24 - 5r

Add 5r to both sides

12r + 5r = 24

17r = 24

Divide both sides by 17

r = 24/17

4) 3x - 8 = -(17 + 2x)

3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

3x = -9 - 2x

Add 2x to both sides

3x + 2x = -9

5x = -9

Divide both sides by 5


\sf (5)/(5)x=(-9)/(5)\\\\\boxed{x = (-9)/(5)}

User Mistalee
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2.8k points