Answer:
Common difference: 30
General term formula:
![a_n=30n-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/6kl3sltjh7vn3rwoqxtflxbt28ih0fi2py.png)
52nd term: 1551
Explanation:
Given sequence:
21, 51, 81, 111
Calculate the difference in terms:
![21 \underset{+30}{\longrightarrow} 51 \underset{+30}{\longrightarrow} 81 \underset{+30}{\longrightarrow} 111](https://img.qammunity.org/2023/formulas/mathematics/high-school/g9q7jbj5yavs9omvmd35dc33i04ghxbn4w.png)
The sequence is increasing by 30 each time, so as there is a common difference, this is an arithmetic sequence with a common difference of 30.
General form of an arithmetic sequence
![a_n=a+(n-1)d](https://img.qammunity.org/2023/formulas/mathematics/high-school/t99kk5roieipg56xa37yseewl9ybc4zh6i.png)
where:
is the nth term- a is the first term
- d is the common difference between consecutive terms
Given:
Substitute the given values into the formula to find the general term formula:
![\implies a_n=21+(n-1)30](https://img.qammunity.org/2023/formulas/mathematics/high-school/cpjmwisvdwg8q36rpft1gjgnacu7f9n3zh.png)
![\implies a_n=21+30n-30](https://img.qammunity.org/2023/formulas/mathematics/high-school/631dm54ld3xm9igw1k9b8yi0p6c6ocx4ye.png)
![\implies a_n=30n-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/kis6hjqdwdxy0f1kzksu4pxamyezbjv2it.png)
To find the 52nd term, simply substitute n = 52 into the found general term formula:
![\implies a_(52)=30(52)-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/nb2oev4356euxv4w4zg08m3wz05zmw0359.png)
![\implies a_(52)=1560-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/kqfb5zr1z8kwosgee6g4hoj45snfxzgqcw.png)
![\implies a_(52)=1551](https://img.qammunity.org/2023/formulas/mathematics/high-school/4emoo3zkfn0mlaz6usvb70xb3j64eys7xy.png)