Answer:
The interior angles of any triangle equal 180. Triangle CDF is an equilateral triangle meaning all of its angles are the same. 180/3=60
Each angle of triangle CDF is 60
1.m<CDF=60
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Isosceles triangles have the 2 base angles the same value while the other angle is another value. IN that instance, the m<a = m<f and the m<a + m<f + m<b=180°
If we find one of the angles of ABF then we can find all of them.
the m<AFB + 35° + m<CFD + m<DFE=180°
we know that the m<CFD is 60
35+60+m<AFB + m<DFE=180
95+m<AFB + m<DFE=180
LEts look at the angle AFD
AFD is 150° and since m<AFD and the m<DFE are supplementary, the angle of DFE is 30
lets test it:
if m<DFE is 30 then
95+m<AFB + 30=180
125+m<AFB=180
m<AFB=55
therefore the m<BAF would also be 55 and the m<ABF would be 70
m<ABF=70
This is because the interior angles of any triangle add up to 180°
I hope this helps and please let me know if i was incorrect
Explanation: