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A scientist records the motion of a dolphin as it jumps from the water. The function`h\left(t\right)=-8t^{2}+32t` models the dolphin’s height in feet above the water after t seconds. Show all work and explain your answers clearly. Use complete sentences.
What is the most reasonable domain for this situation? Explain your answer.

NO ONE IS HELPING ON THIS SITE, PLEASE HELP MEEEEE A scientist records the motion-example-1
User Kpp
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2 Answers

3 votes

Answer:

I don't know the answer but try using 900gle lens and scanning it on homework setting

User Zigii Wong
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Answer:

Range is 0 ≤ h ≤ 32

Explanation:

The height is a function of time and is described as h(t) = -8t² + 32t

h is the y-axis and t is the x axis, so we can write this as y = -8x² + 32 x.

This describes a parabola that opens downward, since the coefficient of the square term is negative. The maximum point for height will be at the vertex of the parabola.

y = ax² + bx + c

The x coordinate of the vertex is at -b/2a

a = -8, b = 32, c = 0

-b/2a = -32/-16 = 2

Maximum height is at x = 2 seconds (we can see this on the graph)

At 2 seconds, y = -8(2²) + 32(2) = -32 + 64 = 32

Again, we can see this on the graph.

The x intercepts are the points where y = 0

0 = -8x² + 32x = 8x(-x +4)

y will be 0 when x is 0 or 4 (confirmed by graph)

So, the height (y) = 0 at time (x) = 0 sec, 4 sec

0 ≤ y ≤ 32

y = h, so 0 ≤ h ≤ 32

I hope this helps.

User Atline
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