Answer:
d. 11:15
Explanation:
1) officer1: distance 75 miles, velocity 60mil/h; officer2: distance 25 miles, velocity 55mil/h;
2) time, which is spent officer1 is: 75/60=1.25[h]=75 [min]. If the officer1 leaves his office at 10:00, the arrival time is 11:15;
3) time which is spent officer2 is: 25/55=5/11[h]≈27[min]. The arrival time is 10:27.
4) finally, the both officers are in the required location at 11:15.