Question

Jane is thirteen years younger than twice Ruby’s age. Nora is 5 years older than Ruby. If their ages sum to 52, find each girl’s age.

Answer 1

Ruby is 15, Jane is 17 and Nora is 20.

Explanation:

Let x represent the age of Ruby.

Jane: 2x - 13

Ruby: x

Nora: x + 5

52 = (x) + (2x - 13) + (x + 5)

52 = x + 2x - 13 + x + 5

52 + 13 - 5 = x + 2x + x

60 = 4x

x = 15

Jane:

2(15) -13

= 17

Nora:

(15) + 5

= 20

Answer 2

J=17 N=20 R=15

Explanation:

J=Jane

R=Ruby

N=Nora

J=2R-13

N=5+R

J+N+R=52

(2R-13)+(5+R)+R=52

Slove for R and plug into each equation