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What is the solution to the system of equation

What is the solution to the system of equation-example-1
User Tony Borf
by
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1 Answer

6 votes

Answer:


x=(-2,(5)/(3) )

Explanation:

1) We will use the matrix method to solve this problem.


\left[\begin{array}{ccc}-2/3&1&3\\1&0&-2\\\end{array}\right]

2) Swap Row₁ and Row₂ to make row reduction easier.


\left[\begin{array}{ccc}1&0&-2\\-2/3&1&3\\\end{array}\right]

3) Apply to Row₂ : Row₂ +
(2)/(3) Row₁.


\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\end{array}\right]

4) Simplify rows.


\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right]

Note: The matrix is now in row echelon form.

The steps below are for back substitution.

5) Apply Row₁ : Row₁ - 0 Row₂.


\left[\begin{array}{ccc}1&0&-2\0\\0&1&5/3\end{array}\right]

6) Simplify rows.


\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right]

Note: The matrix is now in reduced row echelon form.

7) Therefore,


x=-2\\x=(5)/(3)

User Alister Lee
by
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