Question

A spring with a constant of 92N/m is compressed 2.8 cm. How much potential energy is stored in the spring?

PE= J

Answer 1

0.036J

Step-by-step explanation:

Given parameters:

Spring constant , K = 92N/m

Compression = 2.8cm = 0.028m

Unknown:

Potential energy = ?

Solution:

To solve this problem;

P.E =
`(1)/(2)` K e²

K is the spring constant

e is the compression

so;

P.E =
`(1)/(2)` x 92 x 0.028² = 0.036J