Question

A container of gas is initially at 0.25 atm and 0 ˚C. What will the pressure be at 125 ˚C?

Answer 1

0.37atm

Step-by-step explanation:

Given parameters:

Initial pressure = 0.25atm

Initial temperature = 0°C = 273K

Final temperature = 125°C = 125 + 273 = 398K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we use a derivative of the combined gas law;

`(P1)/(T1)` =
`(P2)/(T2)`

P and T are pressure and temperature

1 and 2 are initial and final values

`(0.25)/(273)` =
`(P2)/(398)`

P2 = 0.37atm