Answer:
P₂ = 2.60 atm
Step-by-step explanation:
Given data:
Initial pressure = 2.38 atm
Initial temperature = 25.0 °C
Final pressure = ?
Final temperature = 52.78°C
Solution:
Initial temperature = 25.0 °C (25.0+273 = 298 K)
Final temperature = 52.78°C (52.78+273 = 325.78 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
2.38 atm / 298 K = P₂/325.78 K
P₂ = 2.38 atm × 325.78 K / 298 K
P₂ = 775.35 atm. K /293 K
P₂ = 2.60 atm