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What is the mole fraction of NaBr in

an aqueous solution that contains
20.1% NaBr (weight/weight %)?
Molar Mass
NaBr: 102.89 g/mol
H₂O: 18.016 g/mol
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What is the mole fraction of NaBr in an aqueous solution that contains 20.1% NaBr-example-1
User Gintautas
by
3.2k points

2 Answers

13 votes

Answer:

4.22% NaBr

Step-by-step explanation:

To find the mole fraction of NaBr, you need to (1) determine the mass of the solute (NaBr) and the solvent (H₂O), then (2) convert the mass of the solute and solvent to moles (via the molar masses), and then (3) calculate the mole fraction of NaBr. The final answer should have 3 sig figs to match the sig figs of the given value (20.1%). Because you are given a percent less than 100%, you can assume that the percent (20.1%) is equal to the mass of the solute (20.1 g).

(Step 1)

100% - 20.1 % NaBr = 79.9% H₂O

20.1% NaBr = 20.1 g NaBr

79.9% H₂O = 79.9 g H₂O

(Step 2)

Molar Mass (NaBr): 102.89 g/mol

20.1 g NaBr 1 mole
------------------- x --------------------- = 0.195 mole NaBr
102.89 g

Molar Mass (H₂O): 18.016 g/mol

79.9 g H₂O 1 mole
------------------ x ------------------- = 4.43 moles H₂O
18.016 g

(Step 3)

moles of solute
Mole Fraction = ---------------------------------------------------- x 100%
moles of solute + moles of solvent

0.195 mole NaBr
Mole Fraction = -------------------------------------------------------- x 100%
(0.195 mole NaBr) + (4.43 moles H₂O)

Mole Fraction = 4.22% NaBr

User Nielk
by
3.4k points
13 votes

Answer:

0.0422

Step-by-step explanation:

Right on Acellus

User Prabhat Mishra
by
3.2k points