Question

As seen in the diagram below, Hawa is building a walkway with a width of a feet to go

around a swimming pool that measures 19 feet by 6 feet. If the total area of the pool
and the walkway will be 770 square feet, how wide should the walkway be?

Answer 1

`x= (-25)/(4)+(1)/(4) √(3705)` or
`x= (-25)/(4) + (-1)/(4)√(3705)`

Explanation:

So first you need to find the area of the swimming pool:

19*6 = 114

Next you add the area of the swimming pool and the area of the walkway:

114 + 770 = 884

After this you solve for x using this equation:

(19 +2x) * (6 + 2x) = 884

This would normally find the area of the whole swimming pool area and the walkway but because we know that we can use it to solve for x.

The step-by-step is this:

`4x^(2) +50x+114=884`

`4x^2+50x+114-884=884-884`

`4x^2+50x+114-884=0`

Now we'll use the quadratic formula to simplify it farther:

`x= (-(50) + √((50)^2-4(4)(-770)) )/(2(4))`

`x=(-50 + or - √(14820) )/(8)`

`x= (-25)/(4)+(1)/(4) √(3705)` or
`x= (-25)/(4) + (-1)/(4)√(3705)`

Answer 2

8 feet

Explanation:

you have to calculate :(19+2x)(6+2x)=770

you will get X1=8,X2= negetive some value but measurement cant be negative .if you put X=8 you'll find LHS=RHS