Question

Please help me I do not understand ​

Answer 1

`b=-(-mx-2x+2m-60)/(x);\quad \:x\\e \:0`

Explanation:

Given the expression

`\left(x-2\right)\left(x-m\right)=x^2-bx+60`

switch sides

`x^2-bx+60=\left(x-2\right)\left(x-m\right)`

subtract x² from both sides

`x^2-bx+60-x^2=\left(x-2\right)\left(x-m\right)-x^2`

simplify

`-bx+60=-mx-2x+2m`

subtract 60 from both sides

`-bx+60-60=-mx-2x+2m-60`

simplify

`-bx=-mx-2x+2m-60`

subtract x from both sides; x≠0

`(-bx)/(-x)=-(mx)/(-x)-(2x)/(-x)+(2m)/(-x)-(60)/(-x);\quad \:x\\e \:0`

simplify

`b=-(-mx-2x+2m-60)/(x);\quad \:x\\e \:0`

Thus,

`b=-(-mx-2x+2m-60)/(x);\quad \:x\\e \:0`