Answer:
Explanation:
For #1 and #2 you already have solutions.
#3. A(2, 3), B(0, 6) and C(2,6)
A'(4, 6), B'(0, 12) and C'(4,12)
#4.
= 3 × 2 ÷ 2 = 3 units²
ΔABC ≅ ΔA'B'C' ⇒ = 3 units²
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