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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=-16x^2+212x+139

User Turvy
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1 Answer

3 votes
The answer is 503.39

Hope this helps
User Clayperez
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