Question

Which of the following is equivalent to the radical expression below when x > 0?

Answer 1

c Sorry am not sure

Explanation:

Answer 2

When x>0, the expression
`(√(16x^2) )/(√(8x) )` simplifies to
`A. √(2x)`. The correct option is
`A. √(2x)`.

Let's simplify the expression
`(√((16*x^2)))/(√((8*x)))`

`√(16x^2)` can be simplified to 4x because the square root of 16 is 4 and
`x^2` is x squared.

`√(8x)` can be simplified as
`√(4.2x)` , which further simplifies to
`2√(2x)` because the square root of 4 is 2.

Now, let's substitute these simplified forms back into the expression:

`(4x)/(2√(2x) )`

Simplifying the fraction by canceling out the common factor of 2 in the numerator and denominator gives:

`2x / √(2x)`

This can be rewritten as
`2x. (1)/(√(2x) )`​ , which is equal to
`√(2x)` .

So, when x>0, the expression
`(√(16x^2) )/(√(8x) )` simplifies to
`A. √(2x)`