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Triangle JKL has an area of in2 and a perimeter of in.
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Triangle JKL has an area of in2 and a perimeter of in.

Triangle JKL has an area of in2 and a perimeter of in.-example-1
User Fractalbit
by
4.7k points

1 Answer

3 votes

Answer:

Area = 24 in²

Perimeter = 24in

Explanation:

To find the area given the length of the 3 sides:

a= 8in

b= 6.4in + 3.6in= 10in

c= 6in

Add them together:

8in + 10in + 6in

= 24in²

To find the perimeter you do the same thing:

a= 8in

b= 10in

c= 6in

Add them together

=24in

DO NOT SQUARE THE ANSWER WHEN FINDING PERIMETER

User Montells
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5.0k points
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