Answer:
Angle 1= 54°
Angle 2= 144°
Angle 3 = 126°
Angle 4 = 36°
Explanation:
We are given measures of the angles of a quadrilateral are 3:8:7:2
Let the common ratio = x
The angles will be:
Angle 1= 3x,
Angle 2= 8x,
Angle 3 =7x
Angle 4 =2x
We know that sum of all angles of quadrilateral = 360°
We can write as:
![3x+8x+7x+2x=360](https://img.qammunity.org/2021/formulas/mathematics/college/x9ojwe6swsfhuijuj11jnlq3hkf91pew1f.png)
Solving to find x,
![3x+8x+7x+2x=360\\20x=360\\x=(360)/(20)\\x=18](https://img.qammunity.org/2021/formulas/mathematics/college/29hohjse9yusc1lclqooo0ehw57qqu11gr.png)
We get value of x = 18
Now, finding angles:
Angle 1= 3x = 3(18) = 54°
Angle 2= 8x = 8(18) = 144°
Angle 3 =7x = 7(18) = 126°
Angle 4 =2x = 2(18) = 36°