Question

Identify the k-value that makes the relationship shown in the table below proportional.​

Answer 1

The value of k that makes the relationship shown in the table below proportional is
`\mathbf{(1)/(2)}`

Explanation:

The relation is proportional if
`y=kx \:or\:k=(y)/(x)`

Putting values of x and y to find k.

For x =2 and y =1 k is:
`k=(y)/(x)=(1)/(2)`

For x =4 and y =2 k is:
`k=(y)/(x)=(2)/(4) =(1)/(2)`

For x =6 and y = 3 k is:
`k=(y)/(x)=(3)/(6) =(1)/(2)`

For x = 8 and y = 4 k is:
`k=(y)/(x)=(4)/(8) =(1)/(2)`

For x =10 and y = 5 k is:
`k=(y)/(x)=(5)/(10) =(1)/(2)`

So, The value of k that makes the relationship shown in the table below proportional is
`\mathbf{(1)/(2)}`