Question

PLS HELP!!

Find the zeros of y=x² - 6x-4 by completing the square.
O A. x= 3± √13
OB. x = 3± √5
O C. x = -3± √13
OD. x = ±3

Answer 1

It’s A I just did this

Answer 2

A

Explanation:

y = x² - 6x - 4

(x - 3)² - 3² - 4 = 0

(x - 3)² - 13 = 0

(x - 3)² = 13

x - 3 = ±√13

x = 3 ± √13