Answer:
The linear equation of the graphed line:
Explanation:
Given the points from the graph
Finding the slope between the points
![\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nrlo6m8wdo12tyt9h1mdgp9vd4866t2plg.png)
![\left(x_1,\:y_1\right)=\left(1,\:0\right),\:\left(x_2,\:y_2\right)=\left(3,\:7\right)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jgsudrzhdvezgd0bzd38uzpuhrd9x409yo.png)
![m=(7-0)/(3-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/e6k0e34mhhuy7un2tglfeyldsauh2d7f6s.png)
![m=(7)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t13l9uvu9kf1ljq4ffv0g4hicfq6d4w7y8.png)
We know the slope-intercept form of the line equation
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
Where m is the slope and b is the y-intercept
substituting m = 7/2 and the point (1, 0) to find the y-intercept 'b'
y=mx+b
0 = 7/2(1) + b
0 = 7/2 + b
b = -7/2
b = -3.5
Thus, y-intercept 'b' = -3.5
substituting m = 7/2 and the y-intercept 'b' = -3.5 in the slope-intercept form
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
y=7/2x + (-3.5)
y = 7/2x - 3.5
Thus, the linear equation of the graphed line: