Question

find the values of x that would make the area of the rectangle greater than the area of the triangle.can you help me pls​

Answer 1

`x>3`

Explanation:

`The\ area\ of\ the\ rectangle\ in\ terms\ of\ x=6x\\The\ area\ of\ the\ triangle\ in\ terms\ of\ x=(4(x+6))/(2)=2(x+6) \\Given\ condition:\\The\ area\ of\ the\ rectangle>The\ area\ of\ the\ triangle\\Hence,\\6x>2(x+6)\\Now, as\ practically\ any\ of\ the\ side\ of\ the\ polygons\ cannot\ be\ negative.\\\\Hence,\\6x>2x+12\\6x-2x>2x+12-2x\\4x>12\\(4x)/(4) >(12)/(4) \\x>3`

`Hence,\\x\ could\ be\ any\ real\ number\ greater\ than\ 3.`