Pls can someone help me log10 √(36) + log10 √(2) - log10 √(7) ​

Question

Pls can someone help me


`log10 √(36) + log10 √(2) - log10 √(7)`
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Answer 1

`= log_(10)((6√(2) )/(√(7) ) )`

Explanation:

Given the expression
`log10√(36) + log10√(2) - log10√(7) \\`

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

`log10√(36) + log10√(2) - log10√(7) \\= log_(10)((√(36) * √(2) )/(√(7) ))\\= log_(10)((6√(2) )/(√(7) ) )`