Answer:
0(x-4)
Explanation:
in my working system i mean just when i try on the place of 4 any number can be inserted
$5x-7=13x+17$,here both gives -22 as a result so
$6(x-4)$=6x-24 and to give the same result or 0
$6(x-4)$=0(x-any number )
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