Question

Two stationary point charges of +60.0 uC and +50.0 uC exert a repulsive force

on each other of 175 N. What is the distance between the two charges?

Answer 1

The value is
`r = 0.39279 \ m`

Step-by-step explanation:

From the question we are told that

The first point charge is
`q_1 = 60.0 \mu C = 60 *10^(-6) \ C`

The second point charge is
`q_2 = 50 \mu C = 50 *10^(-6) \ C`

The repulsive force exerted is
`F = 175 \ N`

Generally the repulsive force exerted is mathematically represented as

`F = (k * q_1 * q_2 )/(r^2)`

Here k is the coulomb constant with a value
`k = 9*10^(9)\ kg\cdot m^3\cdot s^(-4) \cdot A^(-2).`

So

`r = \sqrt{( k * q_1 * q_2 )/(F) }`

=>
`r = \sqrt{( 9*10^9 * 60 *10^(-6) * 50 *10^(-6))/(175) }`

=>
`r = 0.39279 \ m`