Question

What is √-11 in the form a+bi?

Answer 1

Given:

The number is
`√(-11)`.

To find:

The a+bi form of given number.

Solution:

We have,

`√(-11)`

It can be written as

`√(-11)=√(-1* 11)`

`√(-11)=√(-1)* √(11)`
`[\because √(ab)=√(a)√(b)]`

`√(-11)=i* √(11)`
`[\because √(-1)=i]`

`√(-11)=√(11)i`

Here, real part is missing. So, it can be taken as 0.

`√(-11)=0+√(11)i`

So, a = 0 and
`b=√(11)`.

Therefore, the a+bi form of given number is
`0+√(11)i`.