Answer:
5.43 miles
Step-by-step explanation:
Required
Determine the distance from school to her home
Given.
[When going to school]
![Speed = 6mph](https://img.qammunity.org/2021/formulas/sat/high-school/9f15lz3k6xpsdzpwcumcvz1m2zygra7oh0.png)
Represent time with t
Distance is calculated as:.
![Distance = Speed * Time](https://img.qammunity.org/2021/formulas/mathematics/high-school/wxewtog1tl71s8wo39jhxpvy6b00cxv0qs.png)
![Distance = 6 * t](https://img.qammunity.org/2021/formulas/sat/high-school/lo16khc10spgax3utebnwhg48vuc9lwva8.png)
![Distance = 6t](https://img.qammunity.org/2021/formulas/sat/high-school/jz69hfparyb5fzsoaotaxdmlf5z1oe14bm.png)
[When coming back from school]
![Speed = 35mph](https://img.qammunity.org/2021/formulas/sat/high-school/72x4pt64v21piwsabjkok5xsuyd4mlvuu5.png)
![Time = \¾\ hour\ lesser](https://img.qammunity.org/2021/formulas/sat/high-school/ediixyv4xgge6dz4tunixbz4hmssy3ldi6.png)
This implies that she spends t - ¾hr when coming back from school.
So,
becomes
![Distance = 35 * (t - \¾)](https://img.qammunity.org/2021/formulas/sat/high-school/2as90ez2vsr53g8p0snt6i3o0wkkcncwpz.png)
![Distance= 35(t - \¾)](https://img.qammunity.org/2021/formulas/sat/high-school/kfu9c6obl4bv09zml4sybmlvj4qb97buiw.png)
[Equate both expressions of distance]
![35(t - \¾) = 6t](https://img.qammunity.org/2021/formulas/sat/high-school/3bngep5dn4o548kuydatqo7xza7871ld5u.png)
[Open Bracket]
![35t - 35 * \¾ = 6t](https://img.qammunity.org/2021/formulas/sat/high-school/8h3bglw0e1ffs697hg29ns7o156ssodx6n.png)
![35t - 26.25 = 6t](https://img.qammunity.org/2021/formulas/sat/high-school/x8b3swoxgji4gr5k50pz91vbso5popa4f5.png)
[Collect like terms]
![35t - 6t = 26.25](https://img.qammunity.org/2021/formulas/sat/high-school/unz4z00vzuxe82n4hfzb5k9hle08aw1juq.png)
![29t = 26.25](https://img.qammunity.org/2021/formulas/sat/high-school/y05mlzhoceikhtqk51eyb39vsfixcmgc8d.png)
[Solve for t]
![t = (26.25)/(29)](https://img.qammunity.org/2021/formulas/sat/high-school/22uqbxr1ink7ph01mxil570c7t9ag4xr5v.png)
![t =0.91](https://img.qammunity.org/2021/formulas/sat/high-school/z2s1ndkm2n4qwpy7ueak3v74n354dcvqr5.png)
[Substitute 0.91 for t in]
![Distance = 6t](https://img.qammunity.org/2021/formulas/sat/high-school/jz69hfparyb5fzsoaotaxdmlf5z1oe14bm.png)
![Distance = 6 * 0.91](https://img.qammunity.org/2021/formulas/sat/high-school/mxrvdfts7sz7n7vsa4p2gtyimixuvdcnl0.png)
![Distance = 5.43\ miles](https://img.qammunity.org/2021/formulas/sat/high-school/cz769q97c4ivhfiexwfg95a3o4sxqtsnrn.png)
Hence, the school is 5.43 miles from her home