Answer:
J = 500 kg-m/s
Step-by-step explanation:
Given that,
Initial speed of the motor, u = 5 m/s
Final speed of the motor, v = 7 m/s
Mass of the boat, m = 250 kg
We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.
J = m(v-u)
J = 250 (7-5)
J = 500 kg-m/s
Hence, the impulse applied by the motor is 500 kg-m/s.