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A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of

250 kg, what was the impulse applied by the motor?

User Aron
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1 Answer

3 votes

Answer:

J = 500 kg-m/s

Step-by-step explanation:

Given that,

Initial speed of the motor, u = 5 m/s

Final speed of the motor, v = 7 m/s

Mass of the boat, m = 250 kg

We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.

J = m(v-u)

J = 250 (7-5)

J = 500 kg-m/s

Hence, the impulse applied by the motor is 500 kg-m/s.

User Ronnie Liew
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