Question

A submarine rises a vertical distance of 200 m to the surface. The distance measured along the submarine's path is 500 m.

Determine the angle of inclination of the submarine's path to the nearest degree.

Answer 1

24°

Explanation:

Oh, okay. So this is like (kinda?) the opposite of what I did in the last one. This time, instead of finding the side length of the imaginary triangle, you are trying to find the angle of elevation (that's what I call it)

sin θ = 200/500

θ = sin^-1 (200/500)

θ = 23.578...

Rounded:

θ = 24°