Question

What is the equation of the line that passes through the point (-5,2) and has a slope of -2/5?

Answer 1

`y = -(2)/(5)x`

Explanation:

We already know the slope of the line: -2/5. So, we can make an equation like this:

`y =- (2)/(5)x + b`

In the question it gives us both x and y in the point (-5,2). You can plug this back into the equation like this:

`2 = -(2)/(5)(-5) + b`

Now, just solve for b to find the y-intercept:

`2 = (10)/(5) + b\\2 = 2 + b\\0 = b`

Because b equals 0 there is you can write the final equation like this:

`y = -(2)/(5)x`

I hope this helps!!

- Kay :)