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What is the equation of the line that passes through the point (-5,2) and has a slope of -2/5?

User Natsu
by
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1 Answer

6 votes

Answer:


y = -(2)/(5)x

Explanation:

We already know the slope of the line: -2/5. So, we can make an equation like this:


y =- (2)/(5)x + b

In the question it gives us both x and y in the point (-5,2). You can plug this back into the equation like this:


2 = -(2)/(5)(-5) + b

Now, just solve for b to find the y-intercept:


2 = (10)/(5) + b\\2 = 2 + b\\0 = b

Because b equals 0 there is you can write the final equation like this:


y = -(2)/(5)x

I hope this helps!!

- Kay :)

User Rachit Tayal
by
7.8k points

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