Question

What is the solution of the quadratic equation (4y-3)^2=72

Answer 1

To solve this quadratic equation, take the square root of both sides.

Since the left side is a perfect square, it will just be reduced to:

4y - 3

For the constant on the right side, the positive and negative roots must be considered.

√72 = ±6√2

Equating the two:

4y - 3 = ±6√2

4y = 3 ± 6√2

y = (3 ± 6√2)/4

y = (3 + 6√2) / 4 = 2.87

and

y = (3 - 6√2) / 4 = -1.37