Question

How do I find the x to this picture

Answer 1

`\boxed {\boxed {\sf x \approx 30.9}}`

Explanation:

This is a right triangle and we are looking for a missing side. We can use the Pythagorean Theorem to find x.

`a^2+b^2=c^2`

where a and b are the legs and c is the hypotenuse.

In this triangle, the legs are 28 and 13 because they make up the right right angle. x is the hypotenuse because it is opposite the right angle.

`a= 28 \\b= 13 \\c= x`

Substitute the values in.

`(28)^2+(13)^2=x^2`

Solve the exponents.

• (28)²=28*28=784
• (13)²=13*13=169

`784+169=x^2`

Add the two numbers.

`{953} =x^2\\`

We want to solve for x, which means we must isolate it.

The x is being squared. The inverse of a square is the square root, so take the square root of both sides of the equation.

`√(953)=√(x^2) \\`

`√(953) = x`

`30.87069808=x`

Let's round to the nearest hundredth. The 7 in the thousandth place tells us to round the 8 to a 9.

`30.9 \approx x`

x is about 30.9