400 views
1 vote
A polynomial has one root that equals 5 -7i. Name one other root of this poynomial.

User Sethammons
by
7.5k points

2 Answers

0 votes

Answer:

(5 + 7i)

Explanation:

recall that the complex conjugate root theorem states that for a polynomial with real coefficients and with a complex root a + bi, then the other root must be the complex conjugate a - bi

in our case we are given that the polynomial (which we will assume to have real coefficients) has a complex root (5 - 7i)

if we compare this with our explaination above, we can see that a = 5 and b = -7.

hence the other root must be the complex conjugate of (5 - 7i) which is (5 + 7i)

User DrZoo
by
8.6k points
4 votes

Answer:

5+7i

Explanation:

User James Hollingshead
by
9.5k points

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