Question

(Fill In The Blanks Plz)

The compound, 3Na3PO4, has _____ molecules, ______ P atoms, and _____ Na atoms. There are _______ total atoms shown in the formula.

Answer 1

No. of Molecules = 18.06 x 10²³ molecules

No. of Atoms of P = 3 atoms

No. of Atoms of Na = 9 atoms

Total No. of Atoms = 24 atoms

Step-by-step explanation:

FOR NUMBER OF MOLECULES:

`No.\ of\ Molecules = (No.\ of\ Moles)(Avigadro's\ Number)\\No.\ of\ Molecules = (3)(6.02\ x\ 10^(23)\ molecules})\\`

No. of Molecules = 18.06 x 10²³ molecules

FOR NUMBER OF P ATOMS:

`No.\ of\ Atoms\ of\ P = (No.\ of\ Moles)(N.\ of atoms of P)\\No.\ of\ Atoms\ of\ P = (3)(1\ atom})`

No. of Atoms of P = 3 atoms

FOR NUMBER OF Na ATOMS:

`No.\ of\ Atoms\ of\ Na = (No.\ of\ Moles)(N.\ of atoms of Na)\\No.\ of\ Atoms\ of\ Na = (3)(3\ atom})`

No. of Atoms of Na = 9 atoms

FOR TOTAL NUMBER OF ATOMS:

`Total\ No.\ of\ Atoms = (No.\ of\ Moles)(N.\ of\ atoms\ of\ Na + No.\ of\ atoms\ of\ P + No.\ of\ atoms\ of\ O)\\ Total\ No.\ of\ Atoms\ = (3)(3\ atoms + 1\ atom + 4\ atoms}) = (3)(8\ atoms)`

Total No. of Atoms = 24 atoms