97.2k views
1 vote
A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?

1 Answer

4 votes

Answer:


2.89 * {10}^(20) \: \: molecules

Step-by-step explanation:

The number of molecules of KCN can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as


2.89 * {10}^(20) \: \: \: molecules

Hope this helps you

User Esben Andersen
by
4.9k points