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Find all solutions of the equation in the interval [0, 2π).

Find all solutions of the equation in the interval [0, 2π).-example-1

1 Answer

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Answer:

x=0

Explanation:


4 \cos(x) = - \sin {}^(2) (x) + 1


4 \cos(x) = 1 - \sin {}^(2) (x)


4 \cos(x) = \cos {}^(2) (x)


4 \cos(x) - \cos {}^(2) (x) = 0


\cos(x) (4 - \cos(x) ) = 0


\cos(x) = 0


x = 0


4 - \cos(x) = 0


\cos(x) = 4

There is no solution here because cosine is undefined it the range is not between -1 and 1 so the only answer is 0.

User Stefano Giraldi
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