2Fe(s) + 3Cl₂(g) →2FeCl₃(s)
mol Fe = 15.52 : 56 g/mol = 0.277
mol FeCl₃ = mol Fe = 0.277 (same coefficient)
mass FeCl₃ = 0.277 x 162.2 g/mol = 44.93 g
% yield = 34.5 : 44.93 = 76.79 %
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