Question

1-4y^2 = 0
Solve the equation

Answer 1

Step-by-step explanation:

`1-4y^2=0\\1^2-(2y)^2=0\\(1-2y)(1+2y)=0\\`

⇒
`1-2y=0` or
`1+2y=0\\`

⇒
`2y=1` or
`2y=-1\\`

⇒
`y= (1)/(2)` or
`y=(-1)/(2)`

P/s:
`A^2-B^2=(A-B)(A+B)`

Ok done. Thank to me :>

Answer 2

Answer: y = 1/2 or y = -1/2

Step-by-step explanation:

First move the 1 to the side with the 0

-4y^2 = -1 // -1 because when you move a number to the other side of the equation you have to multiply -1

Then divide by -4 on each side

y^2 = 1/4

square root each side

|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value

so the answer would be y = 1/2 or -1/2

to check just put it into the equation as y. Both work.